You & maths

# Exercise Set 1.1 – No. 2

2. In each part, determine whether the equation is linear in x and y.

$\large&space;{\color{blue}&space;(a)&space;\;&space;2^{\frac{1}{3}}x+\sqrt{3}y=1}$

The equation $\large&space;{\color{blue}2^{\frac{1}{3}}x+\sqrt{3}y=1}$ is linear in x and y.

$\large&space;{\color{blue}&space;(b)&space;\;&space;2x^{\frac{1}{3}}+\sqrt[3]{y}=1}$

The equation $\large&space;{\color{blue}2x^{\frac{1}{3}}+\sqrt[3]{y}=1}$ is not linear x and y due to the terms $\large&space;{\color{blue}x^{\frac{1}{3}}}$ and $\large&space;{\color{blue}\sqrt[3]{y}}$.

$\large&space;{\color{blue}&space;(c)&space;\;cos(\frac{\pi&space;}{7})x-4y=log3}$

The equation $\large&space;{\color{blue}\;cos({\frac{\pi}{7}})x-4y}$ is linear in and x and y.

$\large&space;{\color{blue}(d)\;{\frac{\pi}{7}}cosx-4y=0}$

The equation $\large&space;{\color{blue}{\frac{\pi}{7}}cosx-4y=0}$ is not linear in x and y due to the term cosx.

(e) xy = 1

The equation xy = 1 is not linear in x and y due to the term xy.

(f ) y + 7 = x

The equation y + 7 = x is linear in x and y.